10x^2+29x-10=0

Solution for 10x^2+29x-10=0 equation:

10x^2+29x-10=0

a = 10; b = 29; c = -10;
Δ = b2-4ac
Δ = 292-4·10·(-10)
Δ = 1241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{1241}}{2*10}=\frac{-29-\sqrt{1241}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{1241}}{2*10}=\frac{-29+\sqrt{1241}}{20}
$